Once formed, the bromonium ion is susceptible to attack by two nucleophiles—chloride ion and bromide ion—and, in fact, a mixture of two products (both produced by anti attack) is formed. This Hydrogen bromide can also be added to an alkene in an anti‐Markovnikov fashion. room temperature). Thus whether substituents are added to the same side … possible stereochemistry of addition where both electrophile and nucleophile bond to the same side of the plane of the double-bonded carbon atoms of an alkene https://www.khanacademy.org/.../alkene-reactions-tutorial/v/hydrohalogenation Depending on the substrate double bond, addition can have different effects on the molecule. The halogen is highly electronegative and will ‘hog’ the electrons between itself and hydrogen. In anti‐Markovnikov additions, the hydrogen atom of the hydrogen halide adds to the carbon of the double bond that is bonded to fewer hydrogen atoms. Hydrohalogenation, an electrophilic alkene addition reaction, is highly useful as a precursor reaction in multi-step organic chemistry synthesis.Understanding the Molecules:H-X molecules such as H-I, H-Br and H-Cl are highly polar molecules. A hydrohalogenation reaction is the electrophilic addition of hydrohalic acids like hydrogen chloride or hydrogen bromide to alkenes to yield the corresponding haloalkanes. After addition to a straight-chain alkene such as C 2 H 4, the resulting alkane will rapidly and freely rotate around its single sigma bond under normal conditions (i.e. The classical example of this is bromination (any halogenation) of alkenes. This means that both halogen atoms will be adding to the carbons of the double bond in a trans fashion. Generally, you’re not going to have much stereoselectivity in this reaction, you’ll form a 50/50 mixture of two enantiomers. Halogens can act as electrophiles to which can be attacked by a pi bond from an alkene. Halogenation of alkenes is an example of an anti-addition (stereospecific). For this to result, the reaction must proceed by a noncarbocation intermediate; thus in the presence of peroxide, the reaction proceeds via a free‐radical mechanism, …